Wednesday, March 14, 2018

nature of metals


Abstract.
 
The main problem is that using X-rays, we have determined the crystal lattices of different materials, and why they are so, and not others are not yet known. For example, copper crystallizes in the fcc lattice, and iron in the bcc, which becomes fcc on heating, this is used for heat treatment of steels. Copper does not change the crystal lattice when heated.
    
There are many factors affecting the crystallization in the literature, so they decided to remove them as much as possible, and the metal model in the article, say so, is ideal, i.e. all atoms are the same (pure metal) without inclusions, without implants, without defects, etc. using the Hall effect and other data on properties, as well as the calculations of Ashcroft and Mermin, my main determining factor for the type of lattice was the core of the atom or ion, which resulted from the transfer of some electrons to the conduction band.
   
It turned out that the metal bond is due not only to the socialization of electrons, but also to external electrons of atomic cores, which determine the direction or type of the crystal lattice.
The change in the type of metal lattice can be connected with the transition of an electron to the conduction band or its return from this zone. Phase transition.
It is shown that in the general case, the metal bond in the closest packages (hec and fcc) between the centrally chosen atom and its neighbors is presumably carried out by means of nine (9) directional bonds, in contrast to the number of neighbors equal to 12 (twelve) (coordination number) .
Probably the "alien" 3 (three) atoms are present in the coordination number 12 stereometrically, and not because of the connection. The answer is to give an experimental test.
 
Introduction
While it is not possible in general to derive from the quantum mechanical calculations the crystal structure of the metal over the electronic structure of the atom, although, for example, Gantshorn and Delinger pointed out a possible relationship between the presence of a cubic body-centered lattice in the subgroups of titanium, vanadium, chromium and the presence of valence d - orbitals. It is easy to see that four hybrid orbitals are directed along four solid cube diagonals and are well suited for coupling each atom to its 8 neighbors in a cubic body-centered lattice. In this case, the remaining orbitals are directed to the centers of the faces of the unit cell and, possibly, can participate in the connection of the atom with its six second neighbors / 3 /.
The first coordination number (K.Ch.1) "8" plus the second coordination number (K.C.2) "6" is equal to "14".

In simple examples, we show that one bond for a diamond at a packing density of 34% and a coordination number of 4 is 34%: 4 = 8.5%.
In a cubic primitive lattice, the packing density is 52% and the coordination number 6 is 52%: b = 8.66%.
In a cubic body-centered lattice, the packing density of 68% and the coordination number 8 are 68%: 8 = 8.5%.
In a face-centered cubic lattice, the packing density is 74% and the coordination number 12 is 74%: 12 = 6.16%, and if 74%: 9 = 8.22%.
In a hexagonal lattice, the packing density is 74% and the coordination number 12 is 74%: 12 = 6.16%, and if 74%: 9 = 8.22%.
Obviously, these 8.66-8.22% carry a certain physical meaning. The remaining 26% is a multiple of 8.66 and 100% hypothetical packing density is possible with 12 links. But is this possibility real?
The outer electrons of the last shell or subshells of the metal atom form a conduction band. The number of electrons in the conduction band affects the Hall constant, the coefficient of all-round compression, and so on.
Let us construct the model of the metal element so that the remaining electrons, after filling the conduction band, the external electrons of the last shell or subshells of the atomic core somehow influenced the structure of the crystal structure (for example: for bcc lattice-8 valence electrons, and for HEC and FCC -12 or 9).
Obviously, to confirm our model it is necessary to compare the experimental and theoretical data on Hall, the coefficient of all-round compression, and so on.
 
GROSS, QUALITATIVE DETERMINATION OF QUANTITY
ELECTRONS IN THE CONDUCTIVITY METAL - ELEMENT.
EXPLANATION OF FACTORS INFLUENCING THE EDUCATION OF TYPE
GRANTS OF THE MONOCRYSTAL AND ON THE SIGN OF THE CONSTANT HALL.
(Algorithm for constructing a model)
 
Let us try to relate the external electrons of the atom of a given element to the structure of its crystal lattice, taking into account the need for directed bonds (chemistry) and the presence of socialized electrons (physics) responsible for galvanomagnetic properties.
 
 
 
 
 
3163/5000
Izmereniya polya Kholla pozvolyayut opredelit' znak nositeley zaryada v zone provodimosti. Odna iz zamechatel'nykh osobennostey effekta Kholla zaklyuchayetsya, odnako, v tom, chto v nekotorykh metallakh koeffitsiyent Kholla polozhitelen, i poetomu nositeli v nikh dolzhny, vidimo, imet' zaryad, protivopolozhnyy zaryadu elektrona /1/. Pri komnatnoy temperature eto otnositsya k sleduyushchim metallam: vanadiy, khrom, marganets, zhelezo, kobal't, tsink, tsirkoniy, niobiy, molibden, ruteniy, rodiy, kadmiy, tseriy, prazeodim, neodim, itterbiy, gafniy, tantal, vol'fram, reniy, iridiy, talliy, svinets /2/. Resheniye etoy zagadki dolzhna dat' polnaya kvantovomekhanicheskaya teoriya tverdogo tela.
Primerno, kak dlya nekotorykh sluchayev primeneniya granichnykh usloviy Borna-Karmana, rassmotrim sil'no uproshchennyy odnomernyy sluchay zony provodimosti. Variant pervyy: tonkaya zamknutaya trubka, polnost'yu zapolnennaya elektronami krome odnogo. Diametr elektrona primerno raven diametru trubki. Pri takom zapolnenii zony, pri lokal'nom peredvizhenii elektrona, nablyudayetsya protivopolozhnoye dvizheniye "mesta" nezapolnivshego trubku, elektrona, to yest' dvizheniye neotritsatel'nogo zaryada. Variant vtoroy: v trubke odin elektron - vozmozhno dvizheniye tol'ko odnogo zaryada - otritsatel'no zaryazhennogo elektrona. Iz etikh dvukh kraynikh variantov vidno, chto znak nositeley, opredelyayemykh po koeffitsiyentu Kholla, v kakoy-to stepeni, dolzhen zaviset' ot napolneniya zony provodimosti elektronami. Risunok 1.

Ris. 1. Skhematicheskoye izobrazheniye zony provodimosti dvukh raznykh metallov (Masshtaby ne soblyudeny).
a) - variant pervyy;
b) - variant vtoroy.
Na poryadok dvizheniya elektronov takzhe budut nakladyvat' svoi usloviya i struktura zony provodimosti, i temperatura, i primesi, defekty, a dlya magnitnykh materialov i rasseyaniye na magnitnykh kvazichastitsakh - magnonakh.
V privedennoy nizhe tablitse netrudno zametit', chto pochti vse metally-sverkhprovodniki v zone provodimosti soderzhat po dva i boleye elektronov ot atoma. Eto metally: tsirkoniy, tsink, vol'fram, vanadiy, talliy, titan, tantal, ruteniy, reniy, svinets, osmiy, niobiy, lantan, iridiy, gafniy, kadmiy, alyuminiy.
Tak kak rassuzhdeniya nashi grubyye, uchityvayem v dal'neyshem poka tol'ko napolneniye zony provodimosti elektronami. Zapolnim zonu provodimosti elektronami tak, chtoby vneshniye elektrony atomnykh ostovov okazyvali vliyaniye na obrazovaniye tipa kristallizatsionnoy reshetki. Predpolozhim, chto chislo vneshnikh elektronov na posledney obolochke atomnogo ostova, posle zapolneniya zony provodimosti, ravno chislu atomov sosedey (koordinatsionnomu chislu) /5/. Koordinatsionnyye chisla GEK, GTSK (geksagonal'noy i granetsentrirovannoy) plotneyshikh upakovok 12 i 18, a ob"yemnotsentrirovannoy reshetki (OTSK) 8 i14 /3/.

Postroim tablitsu s uchetom vysheizlozhennogo. Temperatura komnatnaya .
Element RH 1010 (m3/K) Z.(sht.) Z ostov.(sht.) Tip reshetki

Gde: RH - Postoyannaya Kholla (koeffitsiyent Kholla)
Z - predpolagayemoye chislo elektronov, otdannoye odnim atomom v zonu provodimosti
Z ostov. - chislo vneshnikh elektronov atomnogo ostova na posledney obolochke.
Tip reshetki - tip kristallicheskoy struktury metalla pri komnatnoy temperature i v nekotorykh sluchayakh dlya temperatur fazovykh perekhodov (T).
 
Measurements of the Hall field make it possible to determine the sign of the charge carriers in the conduction band. One of the remarkable features of the Hall effect is, however, that in some metals the Hall coefficient is positive, and therefore the carriers in them must apparently have a charge opposite to the electron charge / 1 /. At room temperature, this refers to the following metals: vanadium, chromium, manganese, iron, cobalt, zinc, zirconium, niobium, molybdenum, ruthenium, rhodium, cadmium, cerium, praseodymium, neodymium, ytterbium, hafnium, tantalum, tungsten, rhenium, iridium , thallium, lead / 2 /. The solution of this puzzle should be given by a complete quantum mechanical theory of a solid.
    
Approximately, as for some cases of application of the Born-Karman boundary conditions, we consider a strongly simplified one-dimensional case of the conduction band. Option one: a thin closed tube, completely filled with electrons except one. The diameter of the electron is approximately equal to the diameter of the tube. With such a filling of the zone, with the local movement of the electron, there is an opposite movement of the "place" of the non-filled tube, the electron, that is, the motion of a non-negative charge. Option two: in the tube of one electron - it is possible to move only one charge - a negatively charged electron. From these two extreme variants it is seen that the sign of carriers, determined from the Hall coefficient, to some extent, should depend on the filling of the conduction band by electrons. Picture 1.




    Fig. 1. Schematic representation of the conduction band of two different metals (Scales not observed).
    
a) - the first option;
    
b) the second option.

    The motion of the electrons will also be imposed by an order of magnitude on the structure of the conduction band, temperature, impurities, and defects, and magnons for magnetic materials and scattering by magnetic quasiparticles.
    
In the table below it is not difficult to see that almost all the superconductor metals in the conduction band contain two or more electrons from the atom. They are metals: zirconium, zinc, tungsten, vanadium, thallium, titanium, tantalum, ruthenium, rhenium, lead, osmium, niobium, lanthanum, iridium, hafnium, cadmium, aluminum.
    
Since our arguments are crude, we take into account in the sequel so far only the filling of the conduction band by electrons. We fill the conduction band with electrons so that the outer electrons of the atomic cores exert influence on the formation of the type of crystallization lattice. Suppose that the number of external electrons on the last shell of the atomic core, after filling the conduction band, is equal to the number of neighbors atoms (coordination number) / 5 /. Coordination numbers of HEC, fcc (hexagonal and face-centered) densest packages 12 and 18, and body-centered lattice (bcc) 8 and 14/3 /.

Let's construct the table taking into account the above. The room temperature.
Element RH 1010 (m3 / K) Z. (pcs.) Z frame (pcs.) Grid type

The below table is filled in compliance with the above judgements.
 ElementRH . 1010
(м3/K)
Z.
(number)
Z kernel
(number)
Lattice type
Na-2,3018body-centered
Mg-0,9019volume-centered
Al-0,3829face-centered
Al-0,38112face-centered
K-4,2018body-centered
Ca-1,7819face-centered
CaT=737K28body-centered
Sc-0,6729volume-centered
Sc-0,67118volume-centered
Ti-2,4019volume-centered
Ti-2,4039volume-centered
TiT=1158K48body-centered
V+0,7658body-centered
Cr+3,6368body-centered
Fe+8,0088body-centered
Fe+8,00214body-centered
FeТ=1189K79face-centered
FeТ=1189K412face-centered
Co+3,6089volume-centered
Co+3,60512volume-centered
Ni-0,6019face-centered
Cu-0,52118face-centered
Cu-0,5229face-centered
Zn+0,90218volume-centered
Zn+0,9039volume-centered
Rb-5,9018body-centered
Y-1,2529volume-centered
Zr+0,2139volume-centered
ZrТ=1135К48body-centered
Nb+0,7258body-centered
Mo+1,9168body-centered
Ru+2279volume-centered
Rh+0,48512face-centered
Rh+0,4889face-centered
Pd-6,8019face-centered
Ag-0,90118face-centered
Ag-0,9029face-centered
Cd+0,67218volume-centered
Cd+0,6739volume-centered
Cs-7,8018body-centered
La-0,8029volume-centered
Ce+1,9239face-centered
Ce+1,9219face-centered
Pr+0,7149volume-centered
Pr+0,7119volume-centered
Nd+0,9759volume-centered
Nd+0,9719volume-centered
Gd-0,9529volume-centered
GdT=1533K38body-centered
Tb-4,3019volume-centered
TbТ=1560К28body-centered
Dy-2,7019volume-centered
DyТ=1657К28body-centered
Er-0,34119volume-centered
Tu-1,8019volume-centered
Yb+3,7739face-centered
Yb+3,7719face-centered
Lu-0,53529volume-centered
Hf+0,4339volume-centered
HfТ=2050К48body-centered
Ta+0,9858body-centered
W+0,85668body-centered
Re+3,1569volume-centered
Os<0412volume-centered
Ir+3,18512face-centered
Pt-0,19419face-centered
Au-0,69118face-centered
Au-0,6929face-centered
Tl+0,24318volume-centered
Tl+0,2449volume-centered
Pb+0,09418face-centered
Pb+0,0959face-centered



 Where: RH - Hall constant (Hall coefficient)
Z is the assumed number of electrons, given by one atom to the conduction band
Z skeleton. - number of outer electrons of the atomic core on the last shell.
The lattice type is the type of crystal structure of the metal at room temperature and in some cases for phase transition temperatures (T).
 
Conclusions.
Despite the crude assumptions, it can be seen from the table that the larger the element atom gives electrons to the conduction band, the more positive the Hall constant, and conversely the Hall constant is negative for the elements that gave one or two electrons to the conduction band, which does not contradict the conclusions of Peierls , as well as the connection between the conduction electrons (Z) and valence electrons (Zost), which cause the crystal structure.
Using the method of counting down from the experimental values of the coefficient of all-round compression to theoretical values using the formulas of Ashcroft and Mermin [1], determining the number Z, one can be sure of its close coincidence with that given in Table 1.
The metallic bond appears to be conditioned by both the socialized electrons and the "valence" electrons-the outer electrons of the atomic core.
The phase transitions of an element from one lattice to another can be explained by transferring one of the outer electrons of the atomic core to the conduction band of the metal or by returning it from the conduction band to the outer shell of the core under the influence of external factors (pressure, temperature).
We tried to give a clue, but we got a new, physicochemical properties of the elements, which are pretty well explained, the riddle is a "coordination number" - 9 (nine) for HCC and HEC. Such a frequent occurrence of the number-9 in the table above suggests that the densest packages are not sufficiently investigated.
 
Appendix 1
Metal bond in the closest packages (HEC, HCC)

    
From the arguments about the number of directed bonds (or pseudo-connections, since there is a conduction band between the neighboring metal atoms), equal to nine in the number of outer electrons of the atomic core for the densest packages, it follows that, by analogy with the bcc lattice (eight neighbor atoms in the first coordination sphere) for HEK and fcc lattices in the first coordination sphere, there should be nine, and we have 12 atoms. But 9 atoms of neighbors bound by any centrally chosen atom are indirectly confirmed by experimental data on the Hall and the modulus of all-round compression (and in the experiments on the de Haas-van Alfene effect, the number of oscillations is a multiple of nine).
    
Hence, for the three atoms out of 12, we must seek differences from the remaining atoms of the coordination sphere.

    Fig.1.1, d, e shows the coordination spheres in the densest hexagonal and cubic packs.


Fig.1.1. Dense Packing.
It should be noted that in the hexagonal packing, the triangles of upper and lower bases are unindirectional, whereas in the hexagonal packing they are not unindirectional.
Fig. 1.1. Tight packing
Let's pay attention, that in a hexagonal packing triangles of the top and bottom bases are turned in one and the same party, and in cubic - in different.

Literature: BF Ormont "Introduction to physical chemistry and crystal chemistry of semiconductors", Moscow, 1968
Appendix 2

Theoretical calculation of the uniform compression modulus (B).

B = (6,13/(rs/ao))5* (10)10 dyne/cm2

Where B is the uniform compression modulus ao is the Bohr radius rs - the radius of the sphere with the volume being equal to
the volume falling at one conductivity electron. 

rs=(3/4p n)1/3, p=3,14
Where n is the density of conductivity electrons.

 
Table 1. Calculation according to Ashcroft and Mermine Element Z rs/ao theoretical calculated
 Zrs/a0B theoreticalB calculated
Cs15.621.541.43
Cu12.6763.8134.3
Ag13.0234.599.9
Al32.0722876.0
Table 2. Calculation according to the models considered in this paper
 Zrs/a0B theoreticalB calculated
Cs15.621.541.43
Cu22.12202.3134.3
Ag22.39111.099.9
Al22.40108.676.0
 
According to / 1 /, the number of Z-electrons in the conduction band was obtained by the authors, presumably based on the valency of the metal over oxygen and hydrogen, and must be questioned, since the experimental data on Hall and the modulus of all-round compression are close to theoretical only for alkali metals. Bcc grating.
 
Of course, the pressure of free-electron gases alone does not completely determine the resistance of the metal to compression, nevertheless in the second case of calculation the theoretical modulus of all-round compression lies closer to the experimental one, on the one hand. Obviously, it is necessary to take into account the second factor-the effect on the module of the "valence" or outer electrons of the atomic core, which determine the crystal lattice.
 
While still studying at the institute, I tried to explain the phase transitions in barium titanate. Since then I have been working on the nature of crystal lattices and different properties of chemical elements. It turned out that when heated, the crystal lattices of lithium and beryllium behave approximately like scandium and titanium lattices.
Therefore I doubted the absolute correctness of the table of elements and developed amendments.
 
 
This article sets out the views on the classification of all known chemical elements, those fundamental components of which the Earth and the entire Universe consists.
The innovation of this work is that in the table of elements constructed according to the Mendeleyev’s law and Van-den- Broek’s rule, new chemical elements with atomic numbers 72-75 and 108-111 are supposedly revealed, and also it is shown that for heavy elements starting with hafnium, the nuclei of atoms contain a larger number of protons than is generally accepted. Perhaps the mathematical apparatus of quantum mechanics missed some solutions because the atomic nucleus in calculations is taken as a point.
All cells in the table are full. If this table takes place, I would like to name groups of elements with the numbers 72-75 and 108-111, the islets of Filipenka Henadzi.

The rule of van den Broeck, a lover of nuclear physics, turned out to be more general than Mendeleyev's periodicity and calculations of quantum mechanics. The table must be filled in all cells according to the law or rule, and if somebody does not fill in, there should be an explanation of this by this law or rule. Therefore, the cells of the physical table were filled in both at http://tableelements.blogspot.com and unknown items with numbers 72-75 and 108-111 appeared. Which required explanation. When considering the results of measuring the charges of nuclei or atomic numbers by James Chadwick, I noticed that the charge of the core of platinum is rather equal not to 78, but to 82, which corresponds to the developed table. For almost 30 years I have raised the question of the repetition of measurements of the charges of atomic nuclei, since uranium is probably more charged than accepted, and it is used at nuclear power plants.

таблица элементов

 
  
H
1
He
2
Li
3
Be
4
B
5
C
6
N
7
O
8
F
9
Ne
10
Na
11
Mg
12
Al
13
Si
14
P1
5
S
16
Cl
17
A
1
K
19
Ca
20
Sc
21
Ti
22
V
23
Cr
24
Mn
25
Fe
26
Co
27
Ni 28Cu
29
Zn
30
Ga
31
Ge
32
As
33
Se
34
Br
35
Kr
36
Rb
37
Sr
38
Y
39
Zr
40
Nb
41
Mo
42
Tc
43
Ru
44
Rh
45
Pd
46
Ag
47
Cd
48
In
49
Sn
50
Sb
51
Te
52
I
53
Xe
54
Cs
55
Ba
56
La
57
Ce
58
Pr
59
Nd
60
Pm
61
Sm
62
Eu
63
Gd
64
Tb
65
Dy
66
Ho
67
Er
68
Tu
69
Yb
70
Lu
71
?
72
?
73
?
74
?
75
Hf
76
Ta
77
W
78
Re
79
Os
80
Ir
81
Pt
82
Au
83
Hg
84
Tl
85
Pb
86
Bi
87
Po
88
At
89
Rn
90
Fr
91
Ra
92
Ac
93
Th
94
Pa
95
U
96
Np
97
Pu
98
Am
99
Cm
100
Bk
101
Cf
102
Es
103
Fm
104
Md
105
No
106
Lr
107
 
 
Our philosophy that it is impossible to describe nature mathematically by one hundred percent was confirmed. But it strives, of course, to such a description is necessary.
    Henadzi Filipenka
 
Each subsequent chemical element is different
from the previous one in that in its core the number of protons
increases by one, and the number of neutrons increases, in
in general, several. In the literature this strange
ratio of the number of neutrons to the number of protons for any
the kernel is not explained. The article proposes a model nucleus,
explaining this phenomenon.
For the construction of the atomic nucleus model, we note that with alpha-
radioactivity of the helium nucleus is approximately equal to the energy.
Therefore, on the outer layer of the core shell, we place all the protons with such
the same number of neutrons. At the same time, on one energy
Only bosons can be in the
outer shell of the alpha-particle nucleus and are. Inside the Kernel
We will arrange the remaining neutrons, whose task will be
weakening of electrostatic fields of repulsion of protons.
Assuming the core to be spherical, and the radii of the proton and neutron
approximately the same, for any element we get the kernel model,
explaining the ratio of the number of neutrons to the number of protons,
which follows from the packing of the nucleus of the atom by nucleons. Low accuracy for light elements.
We construct the table so that to observe the law of Mendeleyev periodicity, the VanDen-Brook rule and to fill all the cells of the table. In quantum mechanics, by default, in each successive element, the charge of the nucleus increases at its center by one, and the electrons fill with spdf configurations. Our nuclear charge is located on the surface, since the number of protons and the number of neutrons in the nucleus are such that protons and neutrons should be in the outer layer of the nucleus, and only neutrons inside, that is, a shell forms on the surface of the nucleus. In addition, protons must be repelled, and also attracted by an electronic fur coat. The question is whether the kernel can be considered a point in the calculations and up to what times? And the question is whether and when the proton will be inside the nucleus. There is also an apparatus of quantum mechanics, which confirmed the law of Mendeleyev. In his calculations, the nucleus and electrons are taken as points.
But if a proton gets into the nucleus for some reason, then the corresponding electron will be on the very "low" orbit. Quantum mechanics still does not notice such electrons. Or in other words, in elements 72-75 and 108-111, some protons begin to be placed inside the nucleus and the charge of the nucleus is screened, in calculations it can not be taken as a point.
I understood this when I thought of Chadwick's experiments on the determination of nuclear charges in particular platinum. If we plot the results from copper through silver to platinum, we see a clear trend on the charge of platinum not 78, but more. I have 82.
This is the correct and real table, not the pieces. Beginning with Hafnium, the number of protons and, correspondingly, neutrons in the nuclei of the elements changes in comparison with what is generally accepted today.
 
 
 
 

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